Math, asked by MʏSᴛᴇʀɪᴏSᴛᴀʀᴋ, 9 months ago

If α and β are roots of quadratic equation 2 x2

- 10 x + 5 = 0 the value of 1/alpah+1/beta




is ………​

Answers

Answered by hiteshkandari
1

Step-by-step explanation:

here in his question I am letting alpha as x and beta as y

so,

we have o find value of

1/x + 1/y

taking L.C.M

( y + x ) / xy

so we have to find the value of above equation,

now,

equation 2x² - 10x + 5 = 0

by this equation ,

x + y = - b / a

x + y = - ( - 10 ) / 2

x + y = 5

now ,

we have to find the value of xy

xy = c / a

xy = 5 / 2

now we have the value

( y + x ) / xy

5 * 2 / 5

2

hope it helps

Answered by anujsing121212
1

Step-by-step explanation:

2x²- 10x+ 5 = 0

by this equation

x+y =-b/a

x+y = -(-10) /2

x+y =5

now we have to find the value of xy

xy = c/a

xy = 5/2

now we have the value

( y+x) / xy

5×( 2/5)

2

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