If α and β are supplementary angles and cosα=3/5, then the value of sinα cosβ + cosα sinβ = ?
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let ABC be. a triangle..having AC=5 AB=4 BC=3
sin a cos bita+cosa sin bita=4/5*4/5+3/5*3/5=
16/25+9/25=25/25=1
sin a cos bita+cosa sin bita=4/5*4/5+3/5*3/5=
16/25+9/25=25/25=1
honeyvishv:
Thank you so much :)
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