if α andβ are the roots of the equation (x-a)(x-b)+c=0,find the roots of the equation (x-α)(x-β)=c.
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as we know:
α + ß = a + b (1)
αß = ab + c (2)
Now, let A, B be the roots of
(x-α)(x-ß) - c = 0 ... 1x² - (α+ß)x + (αß-c) = 0
so, A + B = α + ß = a + b ... from (1)
A·B = αß - c = (ab+c) - c = ab from (2)
thus, A + B = a + b
A·B = ab
The required roots are : a and b.
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