If α and β are the roots of the quadratic equation x2 - 4x - 6 = 0, find
the values of (i) α2
+ β2 (ii) α3
+ β3
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Answer:
we know that we can calculate the roots by -b-√b^2-4ac/2a and-b+√b^2-4ac/2a
so here b=-4, a=1, c=-6
so by calculating we will get Alpha=2-√5
and Beta=2+√5
so (Alpha)^2+(Beta) ^2=18
(Alpha) ^3+(Beta) ^3=56
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