if α and β are the roots of the quadratic equation x²-x-2=0 then α²+β² is equal to 1)5 2)2 3)9 4)-2
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f(x)=x
2
−2x+3 have zeroes α,β
⇒α+β=2
⇒α⋅β=3
Now polynomial having α+2,β+2 as roots is
p(x)=x
2
−(α+2+β+2)x+(α+2)(β+2)
=x
2
−(α+β+4)x+αβ+2(α+β)+4
=x
2
−(2+4)x+3+2(2)+4
⇒x
2
−6x+11
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