If α and β are the roots of x^2+3x+4=0, then find the equation whose roots are α+1 and β+1.
Answers
Answered by
25
alpha+beta=-b/a
i.e a+b=-3 and
alpha.beta= c/a
i.e a.b=4
now
(a+1)+(b+1)=a+b+2=-3+2=-1---------------(1)
and
(a+1)(b+1)=ab+a+b+1=4-3+1=2------------(2)
now required equation can be given as
x²-x(sum of roots)+( product of roots)=0
=> x²-(-1)x+2=0 ( since from 1&2 )
=> x²+x+2=0
is the required Soln
i.e a+b=-3 and
alpha.beta= c/a
i.e a.b=4
now
(a+1)+(b+1)=a+b+2=-3+2=-1---------------(1)
and
(a+1)(b+1)=ab+a+b+1=4-3+1=2------------(2)
now required equation can be given as
x²-x(sum of roots)+( product of roots)=0
=> x²-(-1)x+2=0 ( since from 1&2 )
=> x²+x+2=0
is the required Soln
ahana2147:
hope it help
Answered by
9
Answer:
x^2 +x +2 =0
Please look at the image for step by step explanation.
HOPE IT HELPS YOU MATE!!
Attachments:
Similar questions