If α and β are the two zeros of the polynomial 21y square -y-2. Find the quadratic polynomial whose zeros are 2α and 2β
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21y square-y-2
21y square-7y+6y-2=0
7y(3y-1)+2(3y-1)=0
3y-1=0,7y+2=0
y=1/3,-2/7
Let alpha =1/3 and betta =-2/7
2 alpha =1/3×2
2 betta =-2/7×2
polynomial =(x-2/3)(x+4/7)
=x square-26x/21-8/21
=21x square-26x-8
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