If α and β are the zeroes of a quadratic polynomial 4x 2 + 4x + 1 , then form a quadratic polynomial whose zeroes are 2α and 2β .
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Answered by
33
If α and β are zeroes, then equation will be
x² - (α+β)x + αβ = 0
Given equation is 4x² +4x + 1=0
∴α +β = -4/4 = -1
αβ = 1/4
Now, new zeroes are 2α and 2β
then,
2α+2β = 2(α+β) = 2(-1) = -2
2α×2β = 4αβ = 4×(1/4) = 1
So the quadratic polynomial will be
x² -(-2)x + 1 =0
⇒x² +2x +1 =0
x² - (α+β)x + αβ = 0
Given equation is 4x² +4x + 1=0
∴α +β = -4/4 = -1
αβ = 1/4
Now, new zeroes are 2α and 2β
then,
2α+2β = 2(α+β) = 2(-1) = -2
2α×2β = 4αβ = 4×(1/4) = 1
So the quadratic polynomial will be
x² -(-2)x + 1 =0
⇒x² +2x +1 =0
Answered by
9
equation is 4x² +4x + 1=0
∴α +β = -4/4 = -1
αβ = 1/4
new zeroes are 2α and 2β
then,
2α+2β = 2(α+β) = 2(-1) = -2
2α×2β = 4αβ = 4×(1/4) = 1
: polynomial will be
x² -(-2)x + 1 =0
⇒x² +2x +1 =0
∴α +β = -4/4 = -1
αβ = 1/4
new zeroes are 2α and 2β
then,
2α+2β = 2(α+β) = 2(-1) = -2
2α×2β = 4αβ = 4×(1/4) = 1
: polynomial will be
x² -(-2)x + 1 =0
⇒x² +2x +1 =0
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