Question

 If ∝ and ß are the zeroes of a quadratic polynomial p(x) = x² - 7x + k such that ∝ - ß = 1, find the value of k​​

Answer 1

x^2 - 7x + k = 0

alpha = -b/a = -(-7)/1 = 7

beta = c/a = k/1 = k

given , alpha - beta = 1

7 - k = 1

-k = -6

So, k = 6

hope it helps you