Question

If α and β are the zeroes of quadratic polynomial 2x

2 − 4x + b, find b if 2α + 3β = 8.

Answer 1

Answer:

2x

2x 2

2x 2 −4x+5

2x 2 −4x+5α+β=

2x 2 −4x+5α+β= a

2x 2 −4x+5α+β= a−b

2x 2 −4x+5α+β= a−b

2x 2 −4x+5α+β= a−b =

2x 2 −4x+5α+β= a−b = 2

2x 2 −4x+5α+β= a−b = 2−(−4)

2x 2 −4x+5α+β= a−b = 2−(−4)

2x 2 −4x+5α+β= a−b = 2−(−4) =

2x 2 −4x+5α+β= a−b = 2−(−4) = 2

2x 2 −4x+5α+β= a−b = 2−(−4) = 24

2x 2 −4x+5α+β= a−b = 2−(−4) = 24

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ=

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= a

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac =

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 2

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β)

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1 +

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1 + β

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1 + β1

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1 + β1

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1 + β1 =

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1 + β1 = αβ

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1 + β1 = αβα+β

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1 + β1 = αβα+β

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1 + β1 = αβα+β =

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1 + β1 = αβα+β = 2

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1 + β1 = αβα+β = 25

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1 + β1 = αβα+β = 25

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1 + β1 = αβα+β = 25

2x 2 −4x+5α+β= a−b = 2−(−4) = 24 =2αβ= ac = 25 (α 2 +β 2 )=(α+β) 2 −2αβ=4−5=−1α1 + β1 = αβα+β = 25 HOPE IT HELPS YOU