Question

If α and β are the zeroes of the polynomial ax2+bx+c find the value of α2 β2

Answer 1

Answer:

(b^2 - 2ac)/a^2

Step-by-step explanation:

α and β are the zeroes

So, α + β = -b/a, αβ = c/a

α^2 + β^2 = (α + β)^2 - 2αβ = (-b/a)^2 - 2(c/a) = (b^2 - 2ac)/a^2

Answer 2

Answer:

(b^2 - 2ac)/a^2

Step-by-step explanation:

α and β are the zeroes

So, α + β = -b/a, αβ = c/a

α^2 + β^2 = (α + β)^2 - 2αβ = (-b/a)^2 - 2(c/a) = (b^2 - 2ac)/a^2

Hope it was of help