Question

If ‘α’ and ‘β are the zeroes of the polynomial ax2+bx+c, then the value of 1α+1β is

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Given

α, β are the zeroes of the given polynomial

α + β = ( – b/a)

αβ = (c/a)

Consider, √α/√β +√β/√α

=) α+β/√αβ..

=) [-b/a] divided by√c/√a

=) [-b/a]×√a/√c

=) -b/√ac