If α and β are the zeroes of the polynomial of the quadratic polynomial p(x) x^2-ax+b, then find the value of α^2+β^2
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12
p(x) = x^2 - ax + b
Alpha + Beta = a
and Alpha*Beta = b
Alpha^2 + Beta^2
= ( alpha + beta)^2 - 2 alpha * beta
= ( a)^2 - 2 b
= a^2 - 2b
Alpha + Beta = a
and Alpha*Beta = b
Alpha^2 + Beta^2
= ( alpha + beta)^2 - 2 alpha * beta
= ( a)^2 - 2 b
= a^2 - 2b
jaya101miahra:
thanks brother
Answered by
1
alpha + beta= a
alpha× beta= b
so answer will be a^2-2b
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