If α and β are the zeroes of the polynomial of x²-4x + 3 find the value of alpha to the power4 *beta to the power 2+ alpha to the power 2*beta to the power 4.
Answers
Answered by
2
Answer:
α⁴β²+α²β⁴=108
Step-by-step explanation:
x²-4x+3=0
∴ x²-3x-x+3=0
∴ (x-3)(x-1)=0
∴ α=3, β=1
α⁴β²+α²β⁴
=(3⁴*1)+(3²*1)
=3⁴+3²
=81+27
=108
Amish4567:
nyc answer dear
Answered by
5
Heya
_______________________________
ax² + bx + c = 0
Alfa + Beta = -b/a
And
Alfa × Beta = c/a
_______________________________
Alfa + Beta = -4
And
Alfa × Beta = 3
Alfa⁴ Beta² + Beta⁴ Alaf² =
Alfa² × Beta² { Alfa² + Beta² }
=>
=
9 { 16 - 6 }
=>
Alfa⁴ Beta² + Beta⁴ Alfa² = 90
_______________________________
ax² + bx + c = 0
Alfa + Beta = -b/a
And
Alfa × Beta = c/a
_______________________________
Alfa + Beta = -4
And
Alfa × Beta = 3
Alfa⁴ Beta² + Beta⁴ Alaf² =
Alfa² × Beta² { Alfa² + Beta² }
=>
=
9 { 16 - 6 }
=>
Alfa⁴ Beta² + Beta⁴ Alfa² = 90
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