Math, asked by aazamada20, 8 months ago


If € and ¥ are the zeroes of the polynomial p(x) = 3x - 14x + 15. find the value of €^2 and ¥^2​

Answers

Answered by jpg810
6

Answer:

If your polynomial is

3 {x}^{2}  - 14x + 15 = 0

then your answer is here

3 {x}^{2}  -14x + 15 = 0

3 {x}^{2}  - 9x - 5x + 15 = 0

3x(x - 3) - 5(x - 3) = 0 \\ (x - 3)(3x - 5) = 0

x = 3 \: or \:  \frac{5}{3}

Let € = α

And ¥ = β

 { \alpha }^{2}  =  {3}^{2}

 { \alpha }^{2}  = 9

 { \beta }^{2}  ={  (\frac{5}{3})}^{2}  \\  { \beta }^{2}  =  \frac{25}{9}

 { \beta }^{2}  =  \frac{25}{9}

Hope it helps...

Mark as branliest please...

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