Math, asked by Ayushp4, 1 year ago

If α and β are the zeroes of the polynomial p(x) = 3x² – 5x + 6, find-->

(i) (α / β) + ( β / α )

(ii) α³ + β³

Answers

Answered by srilakshmi23

3x²-5x+6

α+β=-b/a=5/3

αβ=c/a=6/3=2

(ii). α³+β³=(α+β)³-3αβ(α+β)

=(5/3)³-3×2×5/3

=125/27-10

=125-270/10

=-14.5

(i) A/B+B/A=(A^2+B^2)/AB

(A+B)^2= A^2+B^2+2AB

(5/3)^2 = A^2+B^2+2(2)

25/9-4= A^2+B^2

25-36/9=A^2+B^2

-11/9= A^2+B^2

A/B+B/A=( -11/9)/2=-22/9

Ayushp4: I think it's wrong...

Ayushp4: In 1st part you have missed out "/AB"

Ayushp4: From second step it's all wrong because of above mentioned mistake...

Ayushp4: Reply fast or I'll have to take help from brainly team...

Ayushp4: 2nd part is also wrong in calculations...

Ayushp4: See the second last step and the final answer... They aren't matching

Answered by dhruvsingla222

3x²-5x+6

α+β=-b/a=5/3

αβ=c/a=6/3=2

(i) α/β+β/α=(α²+β²)/αβ

(α+β)²= α²+β²+2αβ

(5/3)² = α²+β²+2(2)

25/9-4= α²+β²

(25-36)/9= α²+β²

-11/9= α²+β²

α/β + β/α=( -11/9)/2=-22/9

(ii). α³+β³=(α+β)³-3αβ(α+β)

=(5/3)³-3×2×5/3

=125/27-10

=(125-270)/10

=-145/10

= -14.5

plz make me brainliests

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