If α and β are the zeroes of the polynomial p(x) = ax² + bx + c, then find the value of 1/α³ + 1/β³
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Answer:
(3abc-b³)/c³
Step-by-step explanation:
Given,
α and β are the zeroes of the polynomial p(x) = ax² + bx + c.
To Find :-
1/α³ + 1/β³
Solution :-
We know that :-
Sum of the roots = -(Coefficient of 'x' term)/Constant term
Product of the roots = coefficient of 'x²' term/Constant term.
According to Question :-
α+β = -b/a [ Let it be equation 1]
αβ = c/a[Let it be equation 2]
As we need to find :-
Taking L.C.M :-
=
We know that :-
★a³+b³ = (a+b)³ - 3ab(a + b)
★ a³(b³) = (ab)³
=
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