If α and β are the zeroes of the polynomial p(x) = x² + x + 1, find the value of α² + β².
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p(x) = x² + x + 1
Product of zeroes = ( constant term ) / (coefficient of x²)
==> ɑβ = 1/1
==> ɑβ = 1 ...(1)
Sum of zeroes = -(coefficient of x) / (coefficient of x² )
==> ɑ + β = -1
Square both sides
==> ɑ² + β² + 2ɑβ = (-1)²
==> ɑ² + β² + 2 = 1 { from (1) , ɑβ = 1 }
==> ɑ² + β² = -1
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