Question

if α and β are the zeroes of the polynomial
$p(x) = 3x ^{2} - 14x + 5$
find the values of
$\alpha ^{2} + { \beta }^{2}$
​

Answer 1

Answer:

166/9

Step-by-step explanation:

p(x) = 3x^2 - 14x + 5

a = 3, b = -14, c = 5

Roots are α,β

Sum of roots :

α + β = -b/a

α + β = 14/3

Product of roots:

αβ = c/a

αβ = 5/3

We have to find the value of α²+β²

=> (α+β)² - 2αβ

=> (14/3)² - 2(5/3)

=> 196/9 - 10/3

=> 166/9

#Hope my answer helped you!

Answer 2

Answer:

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