Question

If α and β are the zeroes of the polynomial x
^2-16 than, αβ(α+β) is​

Answer 1

${\red {{\bold{ \huge \dag }}\bold {\huge{{\mathcal {\underline{Answer}}}} \dag}}}$

FOR ANY QUADRATIC EQUATION,

$\bold{{x}^{2} - (sum \: of \: the \: roots)x + product \: of \: roots = 0}$

$\blue {given \: quadratic \: eqn}$

${x}^{2} - 16 = 0$

$\longrightarrow \: {x}^{2} - 0 x - 16 = 0$

HANCE

$\alpha + \beta = 0 \\ \bold{and} \\ \alpha \beta = - 16$

MULTIPLYING,

$\boxed{ \mathfrak{\alpha \beta ( \alpha + \beta ) = 0}}$

HOPE THIS IS HELPFUL

Answer 2

The value of αβ(α + β) = 0.