Question

If α and β are the zeroes of the quadratic polynomial 21y2

– y – 2, find a quadratic polynomial whose

zeroes are 2α and 2β.

Answer 1

Answer:

finding zeros of 21y²-y-2

21y²-7y+6y-2

7y(3y-1)+2(3y-1)

there fore zeros are

7y+2=0 3y-1=0

y=-2/7 y=1/3

there fore alpha=-2/7 beta=1/3

we know that:

p(x)=

$x {}^{2} - \binom{ \alpha + \beta }{} {x} + \alpha \beta$

multiply 2 with the values of alpha and Beta and insert them in the above formula u will get the answer

Answer 2

21x^2 - 2x - 8

solve the question by finding the zeroes and then considering 2alpha and 2beta to get new zeroes and make the new polynomial