Question

If α and β are the zeroes of the quadratic polynomial 6x2+x-2,then the vale of a+b+(a+b)2 is

Answer 1

Answers

Let’s first solve the equation to get our zeroes of the equation i.e. alpha and beta.

6x2+x−2=0

6x2+4x−3x−2=0

2x(3x+2)−(3x+2)=0

which gives us two equations,

2x−1=0=>x=1/2(alpha)

3x+2=0=>x=−2/3(beta)

So, the value of alpha/beta and beta/alpha will be -3/4 and -4/3, adding both of them gives the solution as -25/12

Step-by-step explanation:

main motive to help people

I hope you are satisfied with the answer

please follow me

please follow me

BTS live forever and ever