Question

If α and β are the zeroes of the quadratic polynomial f(x)=2x^2-3x+7, then evaluate 1/α+1/β.

Answer 1

Hello friends!!

Here is your answer :

Given

f(x)=2x²-3x+7

α and β are the zeroes of the f(x)

To find

1/α+1/β

Solution

Sum of Zeroes

α + β = -b/a

α + β = - (-3)/2

α + β = 3/2

Product of Zeroes

α β = c/a

α β = 7/2

=> 1/α+1/β

=>α + β / α β

=> 3/2 / 7/2

=> 3/7

=> 1/α+1/β = 3/7

Hope it helps you ^_^

Answer 2

Answer:

HEY DUDE!!

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