If α and β are the zeroes of the quadratic polynomial f(x)= ax2+bx+c, then α-β=
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If α and β are roots / zero of the quadratic equation
f(x)=ax2+bx2+c
aα+bβ+aβ+bα
=(aα+b)(aβ+b)β(aβ+b)+α(aα+b)
=a2αβ+abαabβ+b2aβ2+bβ+aα2+bα
=a2(αβ)+ab(α+β)+b2a(α2+β2)+b(α+β)
observe, we have
α+β=a−b
αβ=ac
⇒ α2+β2=(α+β)2−2αβ
=a2b2−a2c
Using equations on the right
=a2(ac)+ab(a−b)+b2a(a2b2−a2c)+b(a−b)
=ac−b2+b2ab2−2c−ab2
=ac−2c=a−2
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