If α and β are the zeroes of the quadratic polynomial p(x) = x2 - 3x + 7 find a quadratic polynomial whose zeroes are 1/∝ and 1/β
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Answers
Step-by-step explanation:
Let,
x²-3x-2=0
x²-2x-x-2=0
-x(-x-2)+1(-x-2)=0
(-x-2)(-x+1)=0
-x-2=0 (or) -x+1=0
-x=2. (or) -x= -1
x= -2 (or) x=1
Sum of roots= -2+1= -1
product of roots= -2×1= -2
Quadratic equation:-
X²- (sum of roots) X + product of roots=0
X²-(-1)X+(-2)=0
X²+X-2=0
Thank you
Answer:
Given polynomial is x²-3x+7
It's zeroes are the solutions to the quadratic equation
x²- 3x +7 = 0
Now from the theory of equations, we can say,
α + β = 3
αβ = 7
We have to find a quadratic equation whose roots are 1/α and 1/β.
From the theory of equations,
Sum of Roots S = (1/α + 1/β) = (α+β)/αβ = 3/7
Product of Roots P = 1/αβ = 1/7
The required quadratic equation is x² - Sx + P = 0
Or x² - (3/7)x + (1/7) = 0
Or 7x² - 3x + 1 = 0
This is the answer.
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