Question

If and are the zeroes of the quadratic polynomial. Such that + = 24 and – = 8. Find the quadratic

Polynomial having and if its zeroes. Verify the relation ship between the zeroes and coefficients of the polynomial​

Answer 1

Answer:

Hello !

Since a+b = 24

a-b = 8

therefore, by elimination method,

a=16 & b=8

Now product of zeros = (16×8) = 128,

Since quadratic polynomial is x²-sumx + product,

therefore, quadratic polynomial will be ---

x² - 24x + 128

Now verification,

Sum of zeros = -(coefficient of x) ÷ (coefficient of x²),

16+8= -(24)÷1

24 = 24. proved,

Now, product of zeros = constant term ÷ (coefficient of x²),

16×8=128÷1

128=128,

hence, verified.

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Answer 2

Answer:

Step-by-step explanation:

Since a+b = 24

a-b = 8

therefore, by elimination method,

a=16 & b=8

Now product of zeros = (16×8) = 128,

Since quadratic polynomial is x²-sumx + product,

therefore, quadratic polynomial will be ---

x² - 24x + 128

Now verification,

Sum of zeros = -(coefficient of x) ÷ (coefficient of x²),

16+8= -(24)÷1

24 = 24. proved,

Now, product of zeros = constant term ÷ (coefficient of x²),

16×8=128÷1

128

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