Question

If α and β are the zeroes of the quadratic polynomial x -6x+a, find the value of a,if

2

3 α +2 β =20.​

Answer 1

Answer:

$since \: \alpha \: and \: \beta \:a re \: the \: zeroes \: of \: the \: quadratic \: polynomial \\ so \: \alpha + \beta = - b \div a$

Step-by-step explanation:

now 3a+2b= 20 ....(1)

and a+b = -b/a

a+b= -(-6)/1 [ p(x) = x-6x+a

a= 1 and b= -6]

a+b= 6

3(a+b) = 6×3 [ multiplying by 3]

3a+3 b = 6 ...(2)

Subtracting (1) and (2) we get ,

3a+3b-3a-2b= 6-20

b= -14

putting b= -14 in (1) we get

3a+ 2(-14)= 20

3a= 48

a= 16

hope it helps you

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