If α and ß are the zeroes of y2+ 5y+m, find the value of m such that (α+ ß)2- 2 αß = 24
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Step-by-step explanation:
a+b=-(5)/1=-5 (sum of roots=-b/a)
ab=m/1 (product of roots=c/a)
(a+b)*2-5ab=24
-5*2-5m=24
m=-34/5
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