if ∝ and β are the zeroes the polynomial x2-x-6 find the ∝/β and β/∝
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x²-x-6=0
x²-3x+2x-6=0
x(x-3)+2(x-3)=0
(x+2)(x-3)=0
x=-2,3
∴α=-2,β=3
α/β=-2/3
β/α=-3/2.
x²-3x+2x-6=0
x(x-3)+2(x-3)=0
(x+2)(x-3)=0
x=-2,3
∴α=-2,β=3
α/β=-2/3
β/α=-3/2.
jagjitsembhi34:
thanks
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