If α and β are the zeros of 2x² + 5x + 2. Evaluate α² + β².
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Answer:
Step-by-step explanation:
(Alfa^2 + beta^2) = (alfa + beta)^2 - 2alfa beta
p(x) = 2x^2 + 5x + 2
sum of zeroes = alfa + beta = -b/a = -5/2
product of zeroes = alfa × beta = c/a
= 2/2 =1
Hence alfa^2 + beta^2
=(-5/2)^2 - 2 × 1
=25/4 -2
=17/4
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