If α, β and γ are the zeros of the polynomial f(x) = ax3+bx2+cx+d then find the value of α2+β2+γ2.
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We know (a+b+c)^2= (a^2+b^2+c^2)+(2ab+2bc+2ca)
So let alpha =a beta =b and gama =c
a2+b2+c2= (a+b+c)^2-2(ab+bc+ca)
=(-b/a)^2-2(c/a)
=b^2/a^2-2c/a
Taking lcm
=(b^2-2ac)/a^2 is your answer
If you findt it helpful please mark it as brainliest....
So let alpha =a beta =b and gama =c
a2+b2+c2= (a+b+c)^2-2(ab+bc+ca)
=(-b/a)^2-2(c/a)
=b^2/a^2-2c/a
Taking lcm
=(b^2-2ac)/a^2 is your answer
If you findt it helpful please mark it as brainliest....
Hetarth4:
it is correct
Answered by
22
This should be the correct solution. Kindly mark as brainliest if it is correct.
Hope it helps. Thanks!
Hope it helps. Thanks!
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