If α and β are the zeros of the polynomial f (x) = x ² - p(x+1) - c such that
(α+1)(β+1) = 0 , find the value of c
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Answered by
2
Answer:
1
We have,
f(x)=x
2
−p(x+1)−c=0
f(x)=x
2
−px−(p+c)=0
Since,
α,β are the zeroes of the above polynomial.
So,
α+β=p
αβ=−(p+c)
Since,
(α+1)(β+1)=0
αβ+α+β+1=0
−p−c+p+1=0
−c+1=0
c=1
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Answer:
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