Question

if α and β are the zeros of the polynomial x^2 - 6x + a.find a if x = -2

Answer 1

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Answer:

Given, X= -2

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$p(x) = x {}^{2} - 6x + a \\ 0 = ( - 2) {}^{2} - 6( - 2) + a \\ 0 = 4 + 12 + a \\ a = 16$

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Hence, the value of a is 16.

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Answer 2

Answer:

Letp(x )= x^2-6x+a

x=-2

Putting the value of x in above equation we get

P(x)= (-2)×(-2)+(-6)(-2)+(a)

=4+12+a

=a+16

Since it given that it is the zero of the given polynomial

Therefore ,

P(x)=0

》a+16=0

》a=-16

Hence shown