If α and β are the zeros of the polynomial x2−6x+2 , then (1α+1β)=
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Answered by
22
Answer:
Hey buddy!!
Here is the solution...
α+β = -6, αβ= 2.
α+β = -6, αβ= 2.Therefore, (1/α+ 1/β) = (α+β)/αβ = -6/2 = -3
α+β = -6, αβ= 2.Therefore, (1/α+ 1/β) = (α+β)/αβ = -6/2 = -3We have, ax3 + bx2 + cx + d
Answered by
2
Answer:
Answer is -3.
Step-by-step explanation:
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