if α and β are the zeros of the quadratic polynomial ax²+bx+c,then the value of α+β is
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Answer:
-b/a is value of alpha+beta
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ax2+bx+c=0
α+β=−b/a,αβ=c/a
From the first equation you get: α2+2αβ+β2=b2a2
Then you subtract 4αβ , which is 4c/a: α2−2αβ+β2=b2a2−4ca=b2−4aca2
Take square root of both sides(don’t forget the plus minus) α−β=±b2−4ac−−−−−−−√a
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