Question

If α and β are the zeros of the quadratic polynomial f(x) = 2x2 -5x + 7, find a polynomial whose zeros are 2α+ 3β and 3α+ 2β?
Pls, answer it fast!!!

Answer 1

zeroes of polynomial are 2α and 2β

zeroes of polynomial are 2α and 2βso 

zeroes of polynomial are 2α and 2βso sum of zeroes = 

zeroes of polynomial are 2α and 2βso sum of zeroes = 2α + 2 β

zeroes of polynomial are 2α and 2βso sum of zeroes = 2α + 2 β2(α+β)         from (i)

zeroes of polynomial are 2α and 2βso sum of zeroes = 2α + 2 β2(α+β)         from (i)2(-1)

zeroes of polynomial are 2α and 2βso sum of zeroes = 2α + 2 β2(α+β)         from (i)2(-1)-2

zeroes of polynomial are 2α and 2βso sum of zeroes = 2α + 2 β2(α+β)         from (i)2(-1)-2product of zeroes 

zeroes of polynomial are 2α and 2βso sum of zeroes = 2α + 2 β2(α+β)         from (i)2(-1)-2product of zeroes (2α)(2β)

zeroes of polynomial are 2α and 2βso sum of zeroes = 2α + 2 β2(α+β)         from (i)2(-1)-2product of zeroes (2α)(2β)4αβ

zeroes of polynomial are 2α and 2βso sum of zeroes = 2α + 2 β2(α+β)         from (i)2(-1)-2product of zeroes (2α)(2β)4αβ4 (1/4)                  from (ii)

zeroes of polynomial are 2α and 2βso sum of zeroes = 2α + 2 β2(α+β)         from (i)2(-1)-2product of zeroes (2α)(2β)4αβ4 (1/4)                  from (ii)1 

zeroes of polynomial are 2α and 2βso sum of zeroes = 2α + 2 β2(α+β)         from (i)2(-1)-2product of zeroes (2α)(2β)4αβ4 (1/4)                  from (ii)1 polynomial = 

zeroes of polynomial are 2α and 2βso sum of zeroes = 2α + 2 β2(α+β)         from (i)2(-1)-2product of zeroes (2α)(2β)4αβ4 (1/4)                  from (ii)1 polynomial = x ² - ( sum of zeroes )x + product of zeroes

zeroes of polynomial are 2α and 2βso sum of zeroes = 2α + 2 β2(α+β)         from (i)2(-1)-2product of zeroes (2α)(2β)4αβ4 (1/4)                  from (ii)1 polynomial = x ² - ( sum of zeroes )x + product of zeroesx² - (-2)x +1

zeroes of polynomial are 2α and 2βso sum of zeroes = 2α + 2 β2(α+β)         from (i)2(-1)-2product of zeroes (2α)(2β)4αβ4 (1/4)                  from (ii)1 polynomial = x ² - ( sum of zeroes )x + product of zeroesx² - (-2)x +1x² +2 x+1

zeroes of polynomial are 2α and 2βso sum of zeroes = 2α + 2 β2(α+β)         from (i)2(-1)-2product of zeroes (2α)(2β)4αβ4 (1/4)                  from (ii)1 polynomial = x ² - ( sum of zeroes )x + product of zeroesx² - (-2)x +1x² +2 x+1MARK BRAINLIEST...

Answer 2

Answer:

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