If α and β are the zeros of the quadratic polynomial f(x)= x(x-4), find the value of 1/α +1/β -2αβ.
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I am assuming that you know the values of co efficents theorem since you have asked this.
f(x)=x(x-4)
=x²-4x
In this, a=1;b=-4; and c=0
α+β=-b/a and αβ=c/a
=-(-4)/1 =0/1
=4 =0
Now,
1/α+1/β-2αβ
=(α+β)/αβ-2αβ
=4/0-0
=∞ (any number x/0=∞)
This is the answer i can derive unless there is something wrong from the question
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