Question

If α and β are the zeros of the quadratic polynomial p(y) = 5y² - 7y + 1 , find the value of (1/α) + (1/β) .

Answer 1

1/ α + 1/β = 7

Step-by-step explanation:

p(y) = 5y² - 7y + 1

α and β are the zeroes of the polynominial.

Then α + β = -b/a = 7/5

αβ = c/a  = 1/5

Now 1/ α + 1/β = α + β / αβ = 7/5 / 1/5 = 7

1/ α + 1/β = 7

Answer 2

Step-by-step explanation:

this is the Anwer of the question