If α and β are two zeros of the polynomial 2x²+7x+5 then α²/β+β²/α=
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Answer:
Given the roots of the equation:
2x²+7x+5=0 are α,β
Compare it with:
ax²+bx+c=0
So:
a=2
b=7
and c=5
We know that:
α+β=-b/a
=-7/2...............(1)
α*β=c/a
=5/2.............(2)
Given,
α²/β+β²/α
=α³+β³/α*β
=(α+β)(α²-αβ+β²)/αβ
=(α+β)[(α+β)²-αβ]/αβ
From (1) and (2)
=(-7/2)[(-7/2)²-5/2]/5/2
=[(-7/2)(49/4-5/2)]/5/2
=[(-7/2)(49-10)/4]/5/2
=-7/2*39/4*2/5
=-273/20
=-27.3/2
=-13.65
Hope it helped you!!!
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