if α and β are zeroes of (2x²-5x+3) then find the value of
(a) α/β + β/α
(b) 1/2 alpha + 1/2beta
Answers
Answered by
133
Answer:
Value of :
(a) 4/3
(b) 5/4
Step-by-step explanation:
Given equation is:
2x² - 5x + 3
Now,
→ 2x² - 5x + 3
→ 2x² - (2x + 3x) + 3
→ 2x² - 2x - 3x + 3
→ 2x(x - 1) - 3(x - 1)
→ (x - 1)(2x - 3)
Zero's :
• x - 1 = 0
→ x = 1
• 2x - 3 = 0
→ 2x = 3
→ x = 3/2
α and β are 1 and 3/2.
(a) α/β + β/α
→ 1/(3/2) + (3/2)/1
→ 2/3 + 2/3
→ 4/3
(b) 1/2 α + 1/2 β
→ 1/2 × 1 + 1/2 × 3/2
→ 1/2 + 3/4
→ (2 + 3)/4
→ 5/4
Answered by
599
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★ Step by step explanation :
- Here, we have a quadratic equation (2x² - 5x + 3), α and β are it's zeroes. We had to find out the value of (a) α/β + β/α , (b) 1/2 α + 1/2 β.
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★ Using middle splitting method :
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Now,
★ Solving for (a) and (b) :
- (a) α/β + β/α
- (b) 1/2 α + 1/2 β
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★ More to know :
- α + β = -b/a
- αβ = c/a
Where,
- b is the coefficient of x
- c is constant term
- a is coefficient of x²
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