If α and β are zeroes of 2x2 – 5x + 3, then find the values of:
(i) α2 + β2
(ii) 12 + 12
(iii) +
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P(x)=2x^2-5x+3
P(x)=2x^2-3x-2x+3
P(x)=x(2x-3)-1(2x-3)
P(x)=x-1=0. 2x-3=0
P(x)=x=1. x=3/2
(i) α2 + β2
=(1)^2+(3/2)^2
=1/1+9/4
=(4×1)+(1×9)/4
=4+9/4
=13/4
α2 + β2=13/4
1,3/2 are the zeroes of the quadratic polynomial P(x)=2x^2-5x+3
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