If α and β are zeroes of polynomial f(x)=3x^2-7x-6,find a polynomial whose zeroes are α^2 and β^2.
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Secondary SchoolMath5 points
If α and β are zeroes of the polynomial 6x2 – 7x -3, then form a quadratic polynomial whose zeroes are 1/α and 1/β .
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Ask for details FollowReport by KeshavIssar20.02.2018
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6x^2-7x-3=0
Sum=α+ß
=-b/a
=-(-7)/6
=7/6
Product=αß
=c/a
=-3/6
=-1/2
Sum of new polynomial=1/α+1/ß
=(α+ß) {By substituting}
αß
=7/6+(-1/2)
7/6*(-1/2)
=7/6-3/6
7/6*(-1/2)
=4/6
-7/12
=-8/7
Product of new zeroes=1/α*1/ß
=1/(α*ß) {By substituting}
=1
-1/2
=-2
Required polynomial=k(x^2-[sum of new zeroes]x+[product of new zeroes])
=k(x^2-[-8/7]x+[-2]) {By substituting}
=k(x^2+8x/7-2)
=k(7x^2+8x-14)
7
=7x^2+8x-14(where k=7)
1
Secondary SchoolMath5 points
If α and β are zeroes of the polynomial 6x2 – 7x -3, then form a quadratic polynomial whose zeroes are 1/α and 1/β .
Advertisement
Ask for details FollowReport by KeshavIssar20.02.2018
Answers
6x^2-7x-3=0
Sum=α+ß
=-b/a
=-(-7)/6
=7/6
Product=αß
=c/a
=-3/6
=-1/2
Sum of new polynomial=1/α+1/ß
=(α+ß) {By substituting}
αß
=7/6+(-1/2)
7/6*(-1/2)
=7/6-3/6
7/6*(-1/2)
=4/6
-7/12
=-8/7
Product of new zeroes=1/α*1/ß
=1/(α*ß) {By substituting}
=1
-1/2
=-2
Required polynomial=k(x^2-[sum of new zeroes]x+[product of new zeroes])
=k(x^2-[-8/7]x+[-2]) {By substituting}
=k(x^2+8x/7-2)
=k(7x^2+8x-14)
7
=7x^2+8x-14(where k=7)
brarsehajbrarsehaj:
Zeroes are α^2 and β^2
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u can solve it by dis methd olso hope di helps
plz mark it as brainliest
plz mark it as brainliest
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