If α and β are zeroes of polynomial x² + 18x + 80 then the value of 3α + 3β will be
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Answer:
x²+18x+80
x²+10x+8x+80
x(x+10)+8(x+10)
(x+10)(x+8)
x= -8,-10
let α= -8, β= -10
3α + 3β= 3(-8)+3(-10)
= -24-30
= -54
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