If α and β are zeroes of the polynomial 4x²+3x+7 , find the value of 1/α and 1/β
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Given Equation is 4x^2 + 3x + 7.
On comparing with ax^2 + bx + c, we get a = 4, b = 3, c = 7.
Now,
Sum of roots = -b/a
= > α + β = -3/4
Product of roots = c/a
= > αβ = 7/4.
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Given :
= > 1/α + 1/β
= > (α+β)/αβ
= > (-3/4)/(7/4)
= > -3/7.
Therefore, the value of 1/α + 1/β = (-3/7).
Hope this helps!
siddhartharao77:
:-)
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