if α and β are zeroes of the polynomial x^2-3x+2, then find 1/α + 1/β
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Given : α and β are the zeroes of the polynomial x² - 3x + 2
To find : 1/α + 1/β = ?
Solution > 1.
The given polynomial is x² - 3x + 2
Since α and β are the zeroes of the polynomial,
- α + β = - (- 3)/1 = 3
- αβ = 2/1 = 2
Now, 1/α + 1/β = (β + α)/(αβ) = 3/2
Solution > 2.
The given polynomial is x² - 3x + 2
= x² - 2x - x + 2
= x (x - 2) - 1 (x - 2)
= (x - 2) (x - 1)
The zeroes of the given polynomial be 2 and 1
Let, α = 2 and β = 1
Then, 1/α + 1/β = 1/ 2 + 1/1 = 1/2 + 1 = 3/2
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