Question

if α-β and α+β are zeroes of x³-6x²+8x then find the value of β ​

Answer 1

Answer:

Step-by-step explanation:

Given that;

α - β and α + β are zeroes of x²-6x+8

We know that;

Sum of zeroes = -b/a

⇒ α - β + α + β = - (-6)/1

⇒ 2α = 6

⇒ α = 6 / 2

⇒ α = 3

Also,

We know that ;

Product of zeroes = c / a

⇒ ( α - β ) ( α + β ) = 8 / 1

⇒ α² - β² = 8

⇒ 3² - β² = 8

⇒ - β² = 8 - 9

⇒ - β² = - 1

⇒ β = ±1