Question

if α and β are zeros of QP X^2+6X+9 then find α^2+β^2

Answer 1

let alpha =a
beta = b

a^2+b^2+2ab = (a+b)^2

a^2+b^2= (a+b)^2 - 2ab

a+b= -6
a*b=9

a^2+b^2= 36-18= +18

Answer 2

TAKING X AS ALPHA AND Y AS BETA.

Given- x and y are zeroes of polynomial X^2-6X+9

To find- Value of x^2 + y^2

Solution- Sum of roots(x+y) = -b/a = -(-6)/1 = 6

Product of roots(xy) = c/a = 9/1 = 9

Save them for later...

Now, x^2 + y^2 = (x+y)^2 - 2ab

putting the values,we get

(6)^2 - 2(9)

= 36-18

=18

HOPE THIS HELPS YOUR DOUBTS!!!!!

PLZZ MARK BRAINLIEST IF YOU LIKE. :)