If α and β are zeros of quadratic polynomial f(x)= ax² + bx + c, then evaluate the value of 1/α² +
1/β²
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Answer:
1/a² +1/b² = (b²+a²)/b²a²
= ((a+b)² -2ab)/a²b² eq 1
now
ax²+bx+c
a+b = -b/a
a*b = c/a
putting in eq 1
= (b²-2ac)/c²
Step-by-step explanation:
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