Math, asked by THEmultipleTHANKER, 1 month ago

If α and β are zeros of the polynomial p(x)= 4x² - 2x -3 , find the value of 1/α + 1/β​

Answers

Answered by Anonymous
5

Answer:

p(x) = 4x²-2x+(k-4)

a and 1/a are zeroes of p(x)

we know that α+β = -b/a and αβ = c/a ,since α & β are zeroes of polynomial.

so here α & β are a and 1/a .

αβ = c/a

a * 1/a = (k-4)/4

1 = (k-4)/4

4 = k-4

k = 8

Answered by Anonymous
0

Answer:

a and b are the zeroes of polynomial 4x^2 - 2.x - 3 .

a+b= -(-2)/4, or, a+b = 1/2. …………..(1).

a.b= -3/4. ………………(2)

Dividing eqn (1) by eqn. (2)

(a + b)/a.b = (1/2)/(-3/4).

or, 1/b +1/a = - (2/3). Answer.

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