Question

if α and β are zeros of the polynomial x²+7x+10 then find the value of 1 α 1 β​

Answer 1

${x}^{2} + 7x + 10 \\ \\ splitting \: the \: middle \: term \\ \\ {x}^{2} + 5x + 2x + 10 \\ \\ x(x + 5) + 2(x + 5) \\ \\ (x + 5) (x + 2) \\ \\ \\ so \: (x + 5) = 0 \\ \\ x = - 5 \\ \\ (x + 2) = 0 \\ \\ x = - 2$

$Hence \: the \: value \: of \: \alpha \: and \: \beta \: is - 5 \: and \: - 2 \: respectively$